-[9z-(19z+3)]=3+(9z+8)

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Solution for -[9z-(19z+3)]=3+(9z+8) equation:


Simplifying
-1[9z + -1(19z + 3)] = 3 + (9z + 8)

Reorder the terms:
-1[9z + -1(3 + 19z)] = 3 + (9z + 8)
-1[9z + (3 * -1 + 19z * -1)] = 3 + (9z + 8)
-1[9z + (-3 + -19z)] = 3 + (9z + 8)

Reorder the terms:
-1[-3 + 9z + -19z] = 3 + (9z + 8)

Combine like terms: 9z + -19z = -10z
-1[-3 + -10z] = 3 + (9z + 8)
[-3 * -1 + -10z * -1] = 3 + (9z + 8)
[3 + 10z] = 3 + (9z + 8)

Reorder the terms:
3 + 10z = 3 + (8 + 9z)

Remove parenthesis around (8 + 9z)
3 + 10z = 3 + 8 + 9z

Combine like terms: 3 + 8 = 11
3 + 10z = 11 + 9z

Solving
3 + 10z = 11 + 9z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-9z' to each side of the equation.
3 + 10z + -9z = 11 + 9z + -9z

Combine like terms: 10z + -9z = 1z
3 + 1z = 11 + 9z + -9z

Combine like terms: 9z + -9z = 0
3 + 1z = 11 + 0
3 + 1z = 11

Add '-3' to each side of the equation.
3 + -3 + 1z = 11 + -3

Combine like terms: 3 + -3 = 0
0 + 1z = 11 + -3
1z = 11 + -3

Combine like terms: 11 + -3 = 8
1z = 8

Divide each side by '1'.
z = 8

Simplifying
z = 8

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